.NET Framework - Retrieving XSL data
Asked By bic
22-Jan-10 09:24 PM
Hi,
What do I need to change in order for me to retrieve data with key set to a
value?
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
hotelId
postalCode | shortDescription | HotelProperty/RateInfo"/>
Thanks,
--
bic
Martin Honnen replied to bic
You might better post a sample of the XML input you have and of the
corresponding XML output you want to create.
Assuming you want to process only the 'Hotel' elements with a certain
'hotelId' child element you can make the changes inserted below:
--
Martin Honnen --- MVP XML
http://msmvps.com/blogs/martin_honnen/
I am building a reporting structure using ASP 3.0 code that interacts with an XML file to retrieve nodes / elements of data. I started out by using XSL to define the data and the ASP page spits out all the data with a However - what I realized is that I need to incorporate the defined data in the XML within the body of the ASP page. I need to do the same thing I page, also I need to reference ASP variables throughout the process, I dont need an XSL template and it is limiting me. I did research and found that XQuery appears to to reference the fields syntax-wise in the ASP page like I do in this XSL. Can anyone give me an example of how to open the XML for reference and then how to define the fields itself all within the body of the ASP? Here is a sample of the XSL: xmlns:xsl = "http: / / www.w3.org / 1999 / XSL / Transform"> RIGHT FOR COMMENTS / RATING< / h2> size: 9pt"> - -> data
How do I transform this xml file into html by using this xslt document .NET Framework Hello! I know that this is not the right forum but I hope someone know this anyway. I have one xml file and one xslt file shown below. I want to transform this xml file into html by using this xslt document but I cannot find out why the Here is the documentation I have found How to: Execute an XSLT Transformation from the XML Editor Visual Studio 2010 Other Versions Visual Studio 2008 Visual Studio 2005 0 out of 1 rated this helpful Rate this topic The XML Editor allows you to associate an XSLT style sheet with an XML document, perform the transformation, and view the output. The resulting output from the XSLT transformation a filename is generated in your temporary directory. The file extension is based on the xsl:output element in your style sheet and can be .xml, .txt or .htm. If the Output property specifies a filename with an .htm or .html
XML Deserialize of empty value .NET Framework Hello, I am encountering a strange issue when deserializing a piece of XML. If I have the following XML and try to deserialize it, everything works: If I have the following XML, everything works: BUT if instead I have the following XML, the "margin" element is always 0: Why? Is there a known issue with this format 2005 (1) System.IO.MemoryStream (1) System.IO.StreamReader (1) System.IO.StringReader (1) System.Xml.XmlNode (1) System.IO.Stream (1) XmlSerializerNamespaces (1) The XML is fine, at least based on the other XML examples you provided. So there is something wrong with your deserialization code. But since you
Possible to change XML root element name thru XmlSerializer? .NET Framework If I have this: public class Book { public set;} public string Author {get; set; } } When I XmlSerialize it, the root element of the XML will be Book. I want it to be Book sometimes and at some other time if at all feasible? Any suggestions? Thanks. C# Discussions XmlAttributeOverrides (1) XmlElementAttribute (1) XmlRootAttribute (1) XML Serialization (1) WriteStartElement (1) XmlAttributes (1) StreamWriter (1) StreamReader (1) As far as I know you do not own and do not compile. Note that changing the name in the XML would prevent the type from being able to be deserialized by other code that uses and serialize / deserialize that. Just make that subclass's name be whatever you want the XML to read. Another option is to post- / pre-process the XML. That is, serialize the object, then modify the XML directly. And before deserializing, modify the XML again so that it matches what is needed. Finally, of course, yet another option is
Puzzling xsl problem .NET Framework Hello, I am trying to understand how these 2 kind of files used to generate crm email from objects file 1 version = "1.0"> select = "contact / fullname" / > < / xsl:when> <xsl:otherwise> Valued Customer< / xsl:otherwise> < / xsl:choose> in and make sure that you are still having a great experience using our product(s). We have asked ]]> select = "contact / ownerid / @name" / > < / xsl:when> <xsl:otherwise> a customer service representative< / xsl:otherwise> < / xsl:choose> you are currently using and to give you details about our upcoming